Mathematics, 05.10.2021 14:00 EricaCox1
If tanθ = m/n, prove that: (m sinθ - n cosθ)/(m sinθ + n cosθ) = (m² - n²)/(m² + n²)
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![\rm \: = \: \dfrac{cos\theta\bigg[m\dfrac{sin\theta}{cos\theta} - n\bigg]}{cos\theta\bigg[m\dfrac{sin\theta}{cos\theta} + n\bigg]}](/tpl/images/2491/0626/de409.png)
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If tanθ = m/n, prove that: (m sinθ - n cosθ)/(m sinθ + n cosθ) = (m² - n²)/(m² + n²)...
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