A rocket is launched upward with a velocity of 256 feet per second from the top of a 70-foot building. What is the maximum height attained by the rocket?

9514 1404 393

  1094 ft

Step-by-step explanation:

The initial kinetic energy of the rocket will have been completely converted to potential energy when ...

  1/2v^2 = gh

where v is the initial vertical velocity, g is the acceleration due to gravity, and h is the height attained. Solving for h gives ...

  v^2/(2g) = h

  (256 ft/s)²/(2(32 ft/s²)) = 1024 ft

The rocket will attain a height of 1024 feet above the building, or ...

  1024 ft + 70 ft = 1094 ft . . . . height above the ground

what is all that apply?

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

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