Good afternoon nah I get some help in this question today
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Mathematics, 21.06.2019 13:20
Clara solved the equation 7/3x = β2/3 as shown β 7/3x( 3/7 ) = β2/3 ( 3/7 ) x = β14 what is claraβs error?
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Mathematics, 21.06.2019 19:00
Use the quadratic formula to solve the equation. if necessary, round to the nearest hundredth. x^2 - 23 = 10x a. -1.93, 11.93 b. 1.93, -11.93 c. 1.93, 11.93 d. -1.93, -11.93
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Mathematics, 21.06.2019 20:20
How do the number line graphs of the solutions sets of -23 > x and x-23 differ?
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Mathematics, 21.06.2019 21:00
Rewrite the following quadratic functions in intercept or factored form. show your work. y = x^2 + 7x + 10
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