the coordinates of the point of intersection of lines px + y = 3 and x + 2y = q are (2, -3). find the value of p and q

p = 3 and q = - 4

Step-by-step explanation:

Substitute the coordinates of the solution (2, - 3 ) into the equations and solve for p and q

px + y = 3 , then

2p - 3 = 3 ( add 3 to both sides )

2p = 6 ( divide both sides by 2 )

p = 3

and

x + 2y = q , then

2 + 2(- 3) = q

2 - 6 = q , so

q = - 4

step-by-step explanation:

we are given

since, we have to isolate x on anyone side

so, we can move all x terms on one side

subtract both sides by 2x

add both sides by 9

divide both sides by 4

we get

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: