Ements Question 8
1 pts
(08.02 MC)
Rewrite x2 - 2x - 3-0 in the form (x -a)? - b, where a and b are integers, to determine the a and b
values.
Oa-4 and b3
O a-3 and b 2
Oa-2 and b 1
Oa - 1 and b 4
Question 9
1 pts

Step-by-step explanation:

Given,

x² - 2x - 3 = 0

x² - (3x - x) - 3 = 0

x² - 3x + x - 3 = 0

x(x - 3) + 1(x - 3) = 0

(x - 3)(x + 1) = 0

x = 3 & -1

Now,

a and b are integers

So

a = 3 & b = -1 or

a = -1 & b = 3

a = 3 , b = -1          or            a = -1 , b = 3

Step-by-step explanation:

x² - 2x - 3 = 0

x² - 3x + 1x - 3 = 0

x ( x - 3 ) +1 ( x - 3 ) = 0

( x - 3 ) ( x + 1 ) = 0

So,

x - 3 = 0                   or                x + 1 = 0

x = 0 + 3                                      x = 0 - 1

x = 3                                            x = -1

Therefore,

( x - a) ( x - b )

As a and b are integers

It can be,

a = 3 , b = -1          or            a = -1 , b = 3

Hope this helps you.

Let me know if you have any other questions :-)

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