Using a compass and ruler, construct a circle with a 12 in. radius. Use point A as the center. A. Place the pencil point and the compass point of your compass on a ruler and open to the desired length.

B. Rotate the pencil around on the paper to complete the circle.

C. Mark a center for the circle on your paper.

D. Place the sharp point of the compass on the circle's center on your paper.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

answer: he is 272195

step-by-step explanation: all you have to do is multiple 3535 and 77 and it equals 272195

idk u tell me

step-by-step explanation: