The numerator and denominator of a fraction are in the ratio of 3 to 5. If the numerator and denominator are both increased by 2, the fraction is now equal to 2/3
If n = the numerator and d = the denominator, which of the following systems of equations could be used
to solve the problem?

3n = 5d and 3n + 6 = 2d + 4

5n = 3d and 3n + 6 = 2d + 4

5n = 3d and 4n + 4 = 3d + 6

5n = 3d and 3n + 6 = 2d + 4

Given that the numerator and denominator of a fraction are in the ratio of 3 to 5. When the numerator and denominator are both increased by 2, the fraction is equal to \dfrac{2}{3}.  

We are to select the system of equations that could be used to solve the problem.  

Since n denotes the numerator and m denotes the denominator of the given fraction, so we have:

n/d = 3/5

5n = 3d

(n+2)/(d+2) = 2/3

3(n+2) = 2(d+2)

3n + 6 = 2d + 4

Thus, the required system of equations is,

5n = 3d and 3n + 6 = 2d + 4

Brainliest pweaseee if the answer is clear and correct! <3 ~~~

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

(23*2)-12=x     x=34

step-by-step explanation: