Can some one please help me with this problem

The area of EFGH is 234 m².

Step-by-step explanation:

We know that:

4(AB + BC + CD + DA) = EF + FG + GH + HEEF = 9mAB = CD = 2.25 mDA = BC = 6.5 mArea of EFGH = EF x FG

Work:

4(AB + BC + CD + DA) = EF + FG + GH + HE=> 4(2.25) + 4(6.5) + 4(2.25) + 4(6.5) = 9 + FG + GH + HE=> 9 + 26 + 9 + 26 = 9 + FG + GH + HE=> 26 + 9 + 26 = FG + GH + HE=> FG = 26; GH = 9; HE = 26=> Area of EFGH = EF x FG=> Area of EFGH = 9 x 26=> Area of EFGH = 234 m²

Hence, the area of EFGH is 234 m².

Hoped this helped.