A, B and C lie on a straight line. Given that angle
y
= 120° and angle
z
= 283°, work out
x
.

Ok so we know that a straight line is 180 and so

y+something=180

180-120=60

so that part of it is 60

then we know that all the way around a circle is 360 so

z+somethine=360

360-283=77

and all the angles equals 180 so

60+70+x=180

add

130+x=180

-130

x=50

Hope This Helps!!!

x = 43 degrees

Step-by-step explanation: so assume the angle next to angle y is angle m, and the one to the left of z is angle u.

angle x = 180 - (m + u) (sum of angles in a triangle theorem)

so we need to find m and u

m = 180-y => m = 180-120 = 60

u = 360-z  => u = 360-283 = 77

x = 180 - (77+60) => x = 180-137 = 43

thus out answer, x = 43°

$6.42

step-by-step explanation:

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true