Sum of two numbers 80 and difference is 40. Find two
numbers.

The two numbers are 20 and 60

Step-by-step explanation:

Two numbers: x and y

x + y = 80

x - y = 40

x = y + 40

Substitute x

y + 40 + y = 80

2y + 40 = 80

2y = 40

y = 20

Substitute y, so x = 60

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

$6.42

step-by-step explanation: