Solve by the elimination method. Check your work.

1: x = 19 y = 16 ; 2. x = 5 y = -4

Step-by-step explanation:

To check your work plug the numbers back into one of the equations and see if it's true.

For example:
10(19)-9(16)=46

46=46

1. I distributed 3 to all the numbers so that 9y and -9y would cancel then you add like terms.

2. I distributed -4 to all the numbers so that 4x and -4x would cancel. Then add all like terms.

Once you get x or y plug it back into one problem to get the other variable.

Hope this helps!

#1

(2)×3

--(3)

Subtracting eq(1) from (3)

Put in eq(2)

#2

(2) ×4

Subtracting eq(1) from (3)

Put in eq(2)

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

the awnser is visionary