Hi i have no idea does anyone have an idea ? please

y = 2(x+5)²- 60

Step-by-step explanation:

f(x) = ax² +bx +c,  is the standard form

f(x) = a(x - h)² +k , is the vertex form where the (h, k) is the vertex

y = 2x²+20x -10 ,

factor 2 from the two terms

y = 2(x² +10x) -10,

what perfect square has x² +10x? ... x²+10x +25 = (x+5)²

y = 2(x²+10x+25 )- 50 -10,

add 25 in parenthesis to get a perfect square yet subtract 2*25 = 50 so the equation will stay the same

y = 2(x+5)²- 60,

the equation has the vertex at (-5, -60)

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

answer:

c 60% on edg