Does the point (-1, 2) make the following equations true? i) y = -2x ii) y = x + 3

i) True

ii) True

Step-by-step explanation:

Given :-

Point (-1, 2)

To Find :

Whether the point is a solution of :

Solving :-

Substitute the value of the point in each of the equations.

=> y = -2x

=> 2 = -2(-1)

=> 2 = 2 [∴ The point makes it true]

=> y = x + 3

=> 2 = -1 + 3

=> 2 =  2 [∴ The point makes it true]

true

Step-by-step explanation:

first, you take the y = -2x and plug that into y = x + 3. so your equation should be -2x = x + 3. you then solve for x which comes out to be -1. you then plug the -1 into y = -2x. your equation should be y = -2(-1). solve for y which equals 2. the point that you got from both equations matches the point from the equation given so it is true.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

the answer is a if my teacher taught me correct