Question 4 (1 point)   find the lcd of each fraction: 6/7 and 2/3 a. 7 b. 3 c. 21 d. 30 question 5 (1 point)   find the lcd of each fraction: 7/8 and 1/4 a. 32 b. 8 c. 4 d. 24 question 6 (1 point)   find the lcd of each fraction: 2/5 and 3/7 a. 35 b. 7 c. 5 d. 49 question 7 (1 point)   find the lcd of each fraction: 1/9 and 2/4 a. 4 b. 7 c. 36 d. 9 question 8 (1 point)   convert 2/7 into a fractions with a denominator of 28. a. 2/28 b. 8/28 c. 4/28 d. 6/28 question 9 (1 point)   convert 3/5 into a fractions with a denominator of 15. a. 9/15 b. 3/15 c. 5/15 d. 6/15 question 10 (1 point)   convert 6/9 into a fractions with a denominator of 27. a. 6/27 b. 12/27 c. 9/27 d. 18/27

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb