When asked to write a point-slope equation for a line passing through the points (-2, -2) and (2, 1), a student wrote y - 1 = -3/4(x - 2). how can she fix this to write the correct equation? a - that is the correct equation, no changes are necessary. b - change the sign of the slope. c - distribute -3/4 to each term in parentheses. d - change the minus signs to plus signs. i think it's b, me out a bit. (-3/4 is the slope, it's saying remove the negative sign).

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.