Hexagon defghi is translated 8 units down and 3 units to the right. if the coordinates of the pre-image of point f are (–9, 2), what are the coordinates of f'?

f' = (-6, -6)

step-by-step explanation:

the coordinate specifying vertical position is the y-coordinate. when a point is moved 8 units down, 8 is subtracted from the value of the y-coordinate. 2 - 8 = -6.

the coordinate specifying the horizontal position is the x-coordinate. when a point is moved 3 units to the right, 3 is added to the x-coordinate. -9 +3 = -6.

the image coordinates are:

f' = f + (3, -8) = (-9+3, 2-8)

f' = (-6, -6)

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

the answer is $42.96

step-by-step explanation: