Evaluate the expression for x = 5, y = 3, and z = 14 . 5x−6y+20z over 4yz enter your answer in the box.

Hello from  MrBillDoesMath!

  1 17/24

Steps:

          Evaluate             (5x-6y+20x)/ 4yz when x = 5, y = 3, z = 14

          (5(5) - 6(3) + 20(14))   / 4 (3)(14)          (Substitute in values)

       = (25   - 18    +280)       / 4 (3) (14)         (Evaluate products)

       =  (287) /  4 (3) (14)                                (Evaluate expressions)

      =  287/ 168                                             (4 (3)(14) = 168)

      =  (168  + 119 ) /168                                 287 = 168  + 119

      = (168)/168 + 119/168

      = 1              + 119/168

      = 1  119/168          

       BUT 119 = 17 * 7  (surprise!)  and 168 = 12 * 7 * 2 so answer

    =  1 (17*7)/(12*7*2)

    =  1 (17)/(12*2)                               (Cancel 7's)

    = 1 (17/24)                                    

Regards, MrB    

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions

757764

step-by-step explanation:

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