Complete the equation of the line through (2,-2) and (4,1).

The equation, in slope-intercept form, of the line that passes through points (2,-2) and (4,1), is: y = 3/2x - 5.

Recall:

Given:

(2,-2) and (4,1)

y - 1 = 3/2(x - 4)

y - 1 = 3/2(x) - 3/2(4)

y - 1 = 3/2x - 6

y = 3/2x - 6 + 1

y = 3/2x - 5

Therefore, the equation, in slope-intercept form, of the line that passes through points (2,-2) and (4,1), is: y = 3/2x - 5.

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