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![\bf \begin{cases} g(x)=\cfrac{5-x}{2x-1}\\\\ f(x)=\cfrac{x+5}{2x+1} \end{cases}\qquad g(~~f(x)~~)=\cfrac{5-f(x)}{2[f(x)]+1} \\\\\\ g(~~f(x)~~)=\cfrac{5-\left(\frac{x+5}{2x+1} \right)}{2\left(\frac{x+5}{2x+1} \right)-1}\implies g(~~f(x)~~)=\cfrac{\frac{5(2x+1)-(x+5)}{2x+1}}{\frac{2x+10}{2x+1}-1}](/tpl/images/0141/4577/cf4b3.png)
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G(x)=(5-x)/(2x-1) f(x)= (x+5)/(2x+1) what is g(f(x))...
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