The vertices of δabc are a(1,–2), b(1,1), and c(5,–2). which could be the side lengths of a triangle that is similar but not congruent to δabc? 3, 4, and 5 units 9, 12, and 15 units 6, 4, and 5 units 9, 12, and 5 units

Option B.

Step-by-step explanation:

The vertices of ΔABC are A(1,–2), B(1,1), and C(5,–2).  

Distance  formula:

Using distance formula we get

The length of sides are 3,4 and 5.

We need to find the side lengths of a triangle that is similar but not congruent to ΔABC.

It means the sides of new triangle are 3k, 4k and 5k, where k is a positive number and not equal to 1.

For k=3, the sides of new triangle are

The side lengths of a triangle that is similar but not congruent to ΔABC are 9, 12, and 15 units .

Therefore, the correct option is B.

i think the answer is fried chicken ; >

step-by-step explanation: