The hours of daylight, y, in utica in days, x, from january 1, 2013 can be modeled by the equation y=3.06sin(0.017x-1.40) + 12.23. how many hours of daylight, to the nearest tenth, does this model predict for february 14, 2013? (1) 9.4 (2) 10.4 (3)12.1 (4)12.2

Option (4) 12.2

Step-by-step explanation:

Hours of daylight, y, in Utica in days, x, from January 1, 2013 can be modeled by the equation

y = 3.06 sin ( 0.017x - 1.40 ) + 12.23

We have to calculate the hours of daylight from the given equation for February 14, 2013.

From January 1, 2013 to February 14, 2013 number of days = 31 + 14 = 45 days.

Now we place x = 45 days in the equation

y = 3.06 sin (0.017 × 45 - 1.40) + 12.23

= 3.06 sin ( 0.765 - 1.40 ) + 12.23

= 3.06 sin ( - 0.635 ) + 12.23

= 3.06 ( - 0.0111) + 12.23

= -0.0339 + 12.23 = 12.196 = 12.20

Option (4) 12.2 is the correct answer.

i dont have an answer

step-by-step explanation:

x is the total time in minutes for the free response

you are given number of questions as 15 - m and time per item as 8 minutes

to find x multiply the two givens together:

x = 8 * (15-m) = 8(15-m)