Sandy is upgrading her internet service. fast internet charges $60 for installation $50.45 per month. quick internet has free installation but charges $57.95 per month write an equation that can be used to find the number of months for which the internet service would cost the same

Step-by-step explanation:

Given months as ,

Cost of Fast Internet:

$60 for installation and $50.45 per month for months =

Cost of Quick Internet:

Free installation and $57.95 per month for months =

We want to know in how many months BOTH COSTS WOULD BE SAME. So we EQUATE the expressions for both. We have:

This equation can be solved for x to find the number of months for which the internet service would cost the same.

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9