One leg of an isosceles right triangle measures 5 inches. rounded to the nearest tenth, what is the approximate length of the hypotenuse? 2.5 inches 5.0 inches 7.1 inches 9.8 inches

 7.1 inches

Step-by-step explanation:

Given: One leg of isosceles right triangle = 5 inches

Since in isosceles right triangle , two sides have same side length , therefore the length of the other leg should be 5 inches.

Let H be the hypotenuse of the isosceles right triangle

Now, by Pythagoras Theorem , we have

Hence, the approximate length of the hypotenuse = 7.1 inches

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.