The limit as h approaches 0 of (e^(2+h)-e^2)/h = ?
the answer is e^2; explain how to get that?

First, separate the exponents of the first exponential:



Regroup e² on the numerator:


e² is now a constant that can be brought outside the limit:



This limit is a notable one, and we know it is equal to 1,

therefore:

e² · 1 = e²

It’s going to be d. 4x^2-4x-19’