Assume the random variable x is normally distributed with mean mu equals 50μ=50 and standard deviation sigma equals 7σ=7. find the indicated probability. upper p left parenthesis x greater than 34 right parenthesisp(x> 34)

P(X > 34) = 1 - 0.011 = 0.989

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The probability that the problem asks is 1 subtracted by the pvalue of Z when X = 34. So:

has a pvalue of 0.011.

So

P(X > 34) = 1 - 0.011 = 0.989

step-by-step explanation: