Mathematics, 24.07.2019 13:30 kayladaniels146

What is the interquartile range of 6.3, 6.4, 6.5, 6.6, 6.8, 6.8, 7.5

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Answer from: sduhaime1974

Hello!

First you have to find the median

6.3, 6.4, 6.5, 6.6, 6.8, 6.8, 7.5

The median is 6.6

Next you find quartile 1

quartile 1 is the median of the numbers less than 6.6

6.3, 6.4, 6.5

The median is 6.4

Next you find quartile 3

quartile 3 is the median of the numbers higher than the median

6.8, 6.8, 7.5
gnbhv
The median is 6.8

Then you find the range of quartile 3 and quartile 1

You subtract quartile 1 from quartile 3

6.8 - 6.4 =0.4

The interquartile range is 0.4

Hope this helps!

Answer from: Quest

the system of inequity is

$y\leq -x+4$

$3y> x$

step-by-step explanation:

from the given graph it is noticed that we have two related lines. one is solid and another is dashed.

if a line passing through two points, then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

the solid line passing through the points (0,4) and (4,0).

$y-4=\frac{0-4}{4-0}(x-0)$

$y=-x+4$

the related equation of solid line is $y=-x+4$ .

similarly, find the related equation of dashed line. the dashed liune passing through the points (0,0) and (3,1).

$y-0=\frac{0-1}{3-0}(x-0)$

$3y=x$

the related equation of dashed line is $3y=x$

from the given graph it is noticed that the point (0,1) lies on the shaded region, therefore the point (0,1) must be satisfied by the related equations.

check the related equations by the point (0,1).

$1=-0+4$

$1=4$

this statement is true if the sign of inequality is < instead of equality. since it is an solid line therefore the sign of inequality will be $\leq$ . the required inequality is

$y\leq -x+4$

similarly, check the second related equation.

$3(1)=0$

it is a dashed line, so this statement is true if the sign of inequality is > . the required inequality is

$3y> x$

15 points write a system of inequalities to represent the shaded portion of the graph

Answer from: Quest

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

$\frac{ab}{bc} =\frac{ad}{ab}$

now, we can cross multiply

and we get

$ab\timesab=ad\times bc$

$ab^2=ad\times bc$

so, this could be step to prove it

Seth is using the figure shown below to prove pythagorean theorem using triangle similarity: in the

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What is the interquartile range of 6.3, 6.4, 6.5, 6.6, 6.8, 6.8, 7.5...

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