Find three consecutive even integers such that 4 times the first equals 16 times the sum of the third and the number 2

Consecutive even integers are numbers right in a row with a difference of two because they are even.

x= first integer
x+2= second integer
x+4= third integer

4 * x= 16((x + 4) + 2)
combine like terms in parentheses

4x= 16(x + 6)
multiply 16 by parentheses

4x= (16 * x) + (16 * 6)
4x= 16x + 96
Subtract 16x from both sides

-12x= 96
divide both sides by -12

x= -8 first consecutive even integer

x+2= -6 second cons. even integer
x+4= -4 third cons. even integer

ANSWER: The three consecutive even integers are -8, -6 and -4.

Hope this helps! :)

Multiply 9 and 67. then multiply 3 with 67. lastly the answer that you got for 9x67 is to be subtracted by the answer you got for 3x67

The first digit is in the middle school 100s place