If two aspirin tablets, each having a mass of 325 mg, are dissolved in a full stomach whose volume is 1 l and whose ph is 2, what percent of the aspirin is in the form of neutral molecules?

99.7 %

Explanation:

pH = pKa + log(B/A)

In this case, the basic form is the charged form. The neutral form is the acid, because aspirin is o-acetyl benzoic acid

pKa = -log (ka) = 4.53

2 - 4.53 = log(b/a) = -2.53

10^(-2.53) = 0.00288

so, that means that Base/Acid = 0.0028 / 1

so, total is .00288 + 1 = 1.00288

and the percent of acid is 1/1.00288 x100%= 99.7 %

answer: hey

explanation: