A100 cm3 block of lead weighs 11n is carefully submerged in water. one cm3 of water weighs 0.0098 n. what volume of water does the lead how much does that volume of water what is the buoyant force on the will the lead block sink or float in 3. the same 100 cm3 block of lead is carefully submerged in a container of mercury. one cm3 of mercury weighs 0.13 n. what volume of mercury is how much does that volume of mercury what is the buoyant force on the d) will the lead block sink or float in 4. according to problems 2 and 3, does an object’s density have anything to do with whether or not it will float in a particular liquid? justify your answer.

#1

Volume of lead = 100 cm^3

density of lead = 11.34 g/cm^3

mass of the lead piece = density * volume

so its weight in air will be given as

now the buoyant force on the lead is given by

now as we know that

so by solving it we got

V = 11.22 cm^3

(ii) this volume of water will weigh same as the buoyant force so it is 0.11 N

(iii) Buoyant force = 0.11 N

(iv)since the density of lead block is more than density of water so it will sink inside the water

#2

buoyant force on the lead block is balancing the weight of it

(ii) So this volume of mercury will weigh same as buoyant force and since block is floating here inside mercury so it is same as its weight =  11.11 N

(iii) Buoyant force = 11.11 N

(iv) since the density of lead is less than the density of mercury so it will float inside mercury

#3

Yes, if object density is less than the density of liquid then it will float otherwise it will sink inside the liquid

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