Two carts collide and bounce apart. cart 1 had a momentum of –6 kg • m/s before the collision. cart 2 had a momentum of 10 kg • m/s before the collision. what is the total momentum of the carts after the collision? –16 kg • m/s –10 kg • m/s 4 kg • m/s 10 kg • m/s

Total momentum is 4 kg • m/s

Explanation:

Here as we know that there is no external force on this system

So here by the concept of momentum conservation we know that when there is no external force on a system then total momentum of the system is always conserved

So here we know that

So initial total momentum = final total momentum

so here we have

Total momentum = -6 kg m/s + 10 kg m/s

Total momentum = 4 kg m/s

The total momentum of the carts after the collision is 4 kg-m/s.

(C) is correct.

Explanation:

Given that,

Momentum of first cart = -6 kg

Momentum of second cart = 10 kg-m/s

Using momentum of conservation,

The total momentum of system is conserved.

Here, we know that, there is no external force on the carts.

So,

The total momentum of the cart before the collision is same the total momentum of the cart after the collision.

Therefore,

The initial total momentum = final total momentum

The total momentum is

Hence, The total momentum of the carts after the collision is 4 kg-m/s.

the results is a decrease in air temperature with an increase of altitude.

explanation: