Aperson weighing 0.9 kn rides in an elevator that has a downward acceleration of 1.9 m/s^2. the acceleration of gravity is 9.8 m/s^2. what is the magnitude of the force of the elevator floor on the person? answer in kn and round 4 decimal places.

The magnitude of the force is 0.7255kN

Explanation:

The elevator floor acts on the person with a force that is due to the gravitational acceleration less the downward acceleration of the elevator:

(force of floor F) = (mass of person m) x [ (grav. acceleration g) - (elevator acceleration a) ]

in other words, considering the elevator floor as a reference frame in the Earth's gravitational field, the person's weight decreases due to the downward acceleration, as follows:

We are given the person's weight at rest, 0.9kN, from which the mass can be determined as:

So

well clustered together.

points close on a scatter diagram