5m/swhenhereaches and even steeper slope. if he accelerates at 2 m/s2 for the 5 m slope, how fast is he traveling when he reaches the bottom of the 5 m slope?

Answer :   v = 6.7 m/s

Explanation :

It is given that :

Initial velocity, u = 5 m/s

Acceleration,

Distance, s = 5 m

Using equation of motion:

So, when he reaches the bottom of 5 m slope he is travelling with travelling with 6.7 m/s.

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

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explanation:

the answer is b, have negligible mass