A force of 130 N moves it 22 m = least work done
Work done by an object is given by the product of force and the distance covered by it. Mathematically, it can be written as :
W = F × d
In first case, F = 120 N and d = 25 m
Work done, W = 3000 Joules
In second case, F = 115 N and d = 26 m
Work done, W = 2990 Joules
In third case, F = 130 N and d = 22 m
Work done, W = 2860 Joules
In fourth case, F = 125 N and d = 27 m
Work done, W = 3375 Joules
So, it is clear that the least amount of work is done on a crate is when a force of 130 N is acting and distance covered is 22 m.
work done is least for force = 130 N and distance = 22 m
Work done is defined as the product of force applied and the distance traveled by the object.
For force = 120 N and distance = 25 m
Work = 120 x 25 = 3000 J
For force = 115 N and distance = 26 m
Work = 115 x 26 = 2990 J
For force = 130 N and distance = 22 m
Work = 130 x 22 = 2860 J
For force = 125 N and distance = 27 m
Work = 125 x 27 = 3375 J
So, work done is least for force = 130 N and distance = 22 m.