Atennis ball is hit when it is 1.30 meters above the court. the ball's velocity leaving the racket is 8.08 m/s horizontally, how far away does the ball land?

4.2 m

Explanation:

The time taken by the tennis ball to cover vertical displacement 1.30 m would be the same time in which ball would cover horizontal distance.

Initial velocity of the ball, u = 8.08 m/s in horizontal direction.

Initial velocity in the vertical direction is 0.

consider upward direction as positive and downward direction as negative. The ball free falls under gravity in the vertical direction.

Using the second equation of motion,

y = u t + 0.5 at²

⇒-1.30 m = 0 + 0.5 ×(-9.8m/s²) t²

⇒t = 0.52 s

There is no external force acting in the horizontal direction, thus horizontal distance covered is:

s =  u t ⇒ s = 8.08 m/s × 0.52 s = 4.2 m

Thus, the tennis ball lands 4.2 m far away.

what is the actual question though?

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia