One charge is decreased to one-third of its original value, and a second charge is decreased to one-half of its original value. how will the electrical force between the cahrges compare to the original force
it will decrease to 6 times the original force
it willnincrease to 36 times the original force
it will decrease to one-sixth the original force
it will decrease to one-thirty-sixth the original force

The new force will decrease to one sixth the original value.

Explanation:

It is given that,

One charge is decreased to one-third of its original value, and a second charge is decreased to one-half of its original value.

Let, q₁ is the charge 1

q₂ is the charge 2

Initially, the electrical force between the charges is given by :

...........(1)

Let F' is the new force i.e.

So,

 (from equation 1)

Hence, the new force will decrease to one sixth the original value.

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000