Calculate [h3o+

] of a 0.150 m acetic acid solution.

[H3O+] = 0.00520 M

Explanation:

The dissociation of acetic acid in water is given by the equation;

CH3COOH + H2O<> H3O+ + CH3COO-  

ka =  [H+][C2H3O2-]/[HC2H3O2]

Ka = 1.8 x 10^-5

      = x^2 / 0.150-x  

x = [H3O+]= 0.00520 M  

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