The current in the wires of a circuit is 60.0 milliamps. if the voltage impressed across the ends of the circuit were doubled (with no change in its resistance), then its new current would be milliamps

120 mA

Explanation:

The relationship between voltage, current and resistance in a circuit is given by Ohm's law

where

I is the current

V is the voltage

R is the resistance

In this problem, we have an initial current of

I = 60 mA

Then the voltage is doubled:

V' = 2 V

while the resistance is kept the same:

R' = R

So the new current is

so, the current has doubled. Since I = 60 mA, the new current is

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