On an amusement park ride passengers accelerate straight downward from rest to 22.9 m/s in 2.2 s. what is the average acceleration of the passengers on this ride?

Given,  

Initial Velocity (u) = 0 m/s  

Final Velocity (v) = 25.9 m/s  

Time (t) = 2.5 sec  

avg. acceleration = ?  

avg. acceleration = v-u/t  

avg = 25.9/2.5 = 10.36 m/s²  

avg = 10.36 m/s²

option number c is the right answer.