Aball having a mass of 0.20 kilograms is placed at a height of 3.25 meters. if it is dropped from this height, what will be the kinetic energy of the ball
when it reaches 1.5 meters above the ground?
a.1.2 joules
b.2.2 joules
c.3.4 joules
d.3.6 joules
e.4.3 joules

3.4 Joules

Explanation:

the KE= 1/2 mv^2

By the equation v^2  = u^2  + 2as

where v is the final velocity

u is the initial velocity=0

a is the acceleration=-9.81

s is the displacement = 3.25-1.5=1.75(downwards)=-1.75

v^2= 2(-9.81)(-1.75)

v^2=34.335

KE: 1/2(0.2)(34.335)

=3.4335

=3.4 Joules( rounded to 1 decimal places)

Kinetic energy, KE = 3.43 Joules

Explanation:

It is given that,

Mass of the ball, m = 0.2 kg

Initially, it is placed at a height of 2.25 meters. We need to find the kinetic energy of the ball  when it reaches 1.5 meters above the ground. It can be calculated using the conservation of energy.

To find,

Kinetic energy of the ball when it reaches 1.5 meters above the ground

KE = 3.43 Joules

So, the kinetic energy of the ball is 3.43 joules.

adding a(n) to an electric circuit would increase the magnetic field around a wire;

b. solenoid

a solenoid is a type of electromagnet whose purpose is to generate a controlled magnetic field.

if the purpose of the solenoid is instead to impede changes in the electric current, a solenoid can be more specifically classified as an inductor rather than an electromagnet.

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000