A1400kg automobile moving at a maximum speed of 23m/s on a level circular track of readius of 95m. what is the coefficient of friction?

The coefficient of friction is 0.56

Explanation:

It is given that,

Mass of the automobile, m = 1400 kg

Speed of the automobile, v = 23 m/s

Radius of the track, r = 95 m

The automobile is moving in a circular track. The centripetal force is given by :

............(1)

Frictional force is given by :

...................(2)

= coefficient of friction

g = acceleration due to gravity

From equation (1) and (2), we get :

So, the coefficient of friction is 0.56. Hence, this is the required solution.

1/0.14nm = 10^10/1.4 a lot

not too sure thinking all accelerations are pointed down