A222 kg bumper car moving right at 3.10 m/s collides with a 165 kg bumper car moving 1.88 m/s left find the total momentum of the system.

Total momentum of the system is 378 kg-m/s

Explanation:

It is given that,

Mass of first bumper car, m₁ = 222 kg

Velocity of first bumper car, v₁ = 3.10 m/s (in right)

Mass of other bumper car, m₂ = 165 kg

Velocity of second bumper car, v₂ = -1.88 m/s (in left)

Momentum of the system is given by the product of its mass and velocity. So, the total momentum of this system is given by :

p = 378 kg-m/s

Hence, the total momentum of the system is 378 kg-m/s

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

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explanation:

it has to be b, about 97 percent.