Astring is wrapped around a pulley of radius 3.60 cm , and a weight hangs from the other end. the weight falls with a constant acceleration 3.00 m/s^2 what's the angular acceleration of the pulley?

83.3 rad/s^2

Explanation:

r = 3.6 cm = 0.036 m

a = 3 m/s^2

the relation  between the linear acceleration and angular acceleration is given by

a = r α

where, α is angular acceleration, a be the linear acceleration.

α = a / r

α = 3 / 0.036 = 83.3 rad/s^2

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