Technetium (tc; z = 43) is a synthetic element used as a radioactive tracer in medical studies. a tc atom emits a beta particle (electron) with a kinetic energy (ek) of 4.71 × 10−15 j. what is the de broglie wavelength of this electron (ek = mu2/2)?

Answer : The de-Broglie wavelength of this electron,

Explanation :

The formula used for kinetic energy is,

       ..........(1)

According to de-Broglie, the expression for wavelength is,

or,

     ...........(2)

Now put the equation (2) in equation (1), we get:

 ...........(3)

where,

= wavelength = ?

h = Planck's constant =

m = mass of electron =

K.E = kinetic energy =

Now put all the given values in the above formula (3), we get:

conversion used :

Therefore, the de-Broglie wavelength of this electron,

explanation:

v=uf/(u-f)

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