An aquarium 3 m long, 2 m wide, and 1 m deep is full of water. find the work needed to pump half of the water out of the aquarium. (use the fact that the density of water is 1000 kg/m3, and use 9.8 m/s2 for g.)

work is 29430 J

Explanation:

Given data

long = 3 m

wide = 2 m

deep = 1 m

to find out

work needed to pump

solution

first we find out horizontal cross section area

i.e. area = long × wide

cross section area = 3  × 2 = 6

we can say if thickness dx is infinite than volume will be

dv that is equal to 6  × dx

so dv = 6 dx

and here force due to gravity will  be

df =  ρ × g × dv

that will be

df = 6 × ρ × g × dx

and work will be to lift distance x is

dw = df × (x)

so dw =  6 × (x) × ρ × g × dx

now we calculate work half of water out

we consider here full tank is top half so take derivative 0 to 1

so work = 6 × ρ × g ×

work = 6 (1000) (9.81) (1/2)

work is 29430 J

a

explanation:

because they are cartillidge

depends on what you mean by "group." for order, it would be coleoptera (beetles). for class, it would be insecta (insects). for phylum, it would be the arthropoda (animals with jointed exoskeletons).

explanation: