Calculate the number of free electrons per cubic meter for some hypothetical metal, assuming that there are 1.3 free electrons per metal atom. the electrical conductivity and density are 6.8 × 107 (ω-m)-1 and 10.5 g/cm3, respectively, and its atomic weight is 107.87 g/mol. use scientific notation.

The number of free electrons per cubic meter is

Explanation:

It is given that,

The number of free electrons per cubic meter is, 1.3

Electrical conductivity of metal,

Density of metal,

Atomic weight, A = 107.87 g/mol

Let n is the number of  free electrons per cubic meter such that,

Where

is the density of silver atom

is the Avogadro number

A is the atomic weight of silver

or

Hence, this is the required solution.

i wanna say it’s between b and d, leaning more towards b.

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