Ablock whose weight is 45 n rests on a horizontal table. a horizontal force of 36 n is applied to the block. the coefficient of kinetic and static friction are 0.65 and 0.42, respectively. will the block move under the influence of the force, and if so, what will be the blocks acceleration?

The block will move since the horizontal force is greater than the static frictional force.

The acceleration of the block under the influence of the force is 1.47 m/s².

The given parameters;

The mass of the block is calculated as follows;

The static frictional force on the block is calculated as follows;

The block will move since the horizontal force is greater than the static frictional force.

The acceleration of the block is calculated as follows;

Thus, the acceleration of the block under the influence of the force is 1.47 m/s².

Learn more here:link

1.5 m/s²

Explanation:

For the block to move, it must first overcome the static friction.

Fs = N μs

Fs = (45 N) (0.42)

Fs = 18.9 N

This is less than the 36 N applied, so the block will move.  Since the block is moving, kinetic friction takes over.  To find the block's acceleration, use Newton's second law:

∑F = ma

F − N μk = ma

36 N − (45 N) (0.65) = (45 N / 9.8 m/s²) a

6.75 N = 4.59 kg a

a = 1.47 m/s²

Rounded to two significant figures, the block's acceleration is 1.5 m/s².

Usually the coefficient of static friction is greater than the coefficient of kinetic friction.  You might want to double check the problem statement, just to be sure.

a is the best answer your welcome