Find the wavelength of the balmer series spectral line corresponding to n = 12.

The wavelength of the Balmer series spectral line corresponding to n = 12 is 375 nm.

Explanation:

let λ be the wavelrngth of the spectral line.

let ni be the initial energy state, for Balmer series, ni = 4.

let nf be the final energy level, n = 12.

Balmer series states the following:

1/λ = R[1/(ni)^2 - 1/(nf^2))

λ = 1/[R[1/(ni)^2 - 1/(nf^2))]

  = 1/[(1.09737×10^7)×[1/(4)^2 - 1/(12^2))]

  = 375 nm

Therefore, the wavelength of the Balmer series spectral line corresponding to n = 12 is 375 nm.

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86%

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the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form