You are to drive to an interview in another town, at a distance of 300 km on an expressway. the interview is at 11: 15 a. m. you plan to drive at 100 km/h, so you leave at 8: 00 a. m. to allow some extra time. you drive at that speed for the first 120 km, but then construction work forces you to slow to 42.0 km/h for 43.0 km. what would be the least speed needed for the rest of the trip to arrive in time for the interview?

Explanation:

As we know that the distance moved by the car is given 300 km

first it move for 120 km with speed

v = 100 km/h

so the time taken by car to move this distance is

Now it moves next 43.0 km with speed 42 km/h

so the time taken by it is given as

now total time of journey is

time remaining to cover the last part of journey is

now the remaining distance is

so the speed of the car is given as

measure their densities same density, same sub

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer