An electric point charge of q1 = 7.85 nc is placed at the origin of the real axis. another point charge of q2 = 3.67 nc is placed at a position of p = 2.88 m on the real axis. at which position can a third point charge of q = -3.47 nc be placed so that the net electrostatic force on it is zero? let the sign of q2 be changed from positive to negative. at which position can the point charge q be placed now so that the net electrostatic force on it is zero?

I'll do it rn and then answer

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j