Asuper snail initially traveling at 2 m/s accelerates at 1 m/s^2 for 5 seconds. how fast will it be going at the end of the 5 seconds? how far did the snail travel?

The snail travel at the end of 5 s with a velocity of 12 m/s and the distance of the snail is 22.5 m.

Explanation:

Given that, the initial velocity of the snail is,

And the acceleration of the snail is,

And the time taken by the snail is,

Now according to first equation of motion,

Here, u is the initial velocity, t is the time, v is the final velocity and a is the acceleration.

Now substitute all the variables

Therefore, the snail travel at the end of 5 s with a velocity of 7 m/s.

Now according to third equation of motion.

Here, u is the initial velocity, a is the acceleration, s is the displacement, v is the final velocity.

Substitute all the variables in above equation.

Therefore the distance of the snail is 22.5 m.

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c. 7/3

step-by-step explanation:

a rational number is like pi- it is a repeating decimal.

a. is -1.8

b. 2.236068

c. 2.3333333333333333333

d.   is 3

i hope that ! =)